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JEE Advanced Maths Formulas 2026: Free Formula Sheet PDF

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JEE Advanced Mathematics Formulas: Complete Formula Sheet for Effective Revision

JEE Advanced 2026 preparation becomes much easier when all important Maths formulas are available in one place for quick revision. Vedantu’s JEE Advanced Maths Formulas PDF brings together essential formulas from Algebra, Calculus, Coordinate Geometry, Trigonometry, Vectors, and Probability in a simple and easy-to-access format.


This formula sheet helps students revise key concepts quickly, improve accuracy in problem-solving, and save valuable preparation time before the exam. Download the FREE JEE Advanced Maths Formulas PDF and strengthen your revision strategy for 2026.

Competitive Exams after 12th Science
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JEE Advanced Maths Formulas - Quick Reference

CIRCLE

Area of a Circle:

In terms of radius: A = πr² In terms of diameter: A = (π/4) × d²


Surface Area of a Circle:

S = πr²


General Equation of a Circle:

(x − h)² + (y − k)² = r² Centre = (h, k), Radius = r


Standard Equation of a Circle:

(x − a)² + (y − b)² = r² Centre = (a, b), Radius = r


Diameter of a Circle:

D = 2 × radius


Circumference of a Circle:   

C = 2πr


General Form:

x² + y² + 2gx + 2fy + c = 0 Centre = (−g, −f), Radius = √(g² + f² − c)


Intercepts Made by Circle x² + y² + 2gx + 2fy + c = 0:

On x-axis: 2√(g² − c) On y-axis: 2√(f² − c)


Parametric Equations of a Circle:

x = h + r cosθ y = k + r sinθ


Tangent to Circle x² + y² = a²:

Slope form: y = mx ± a√(1 + m²) Point form: xx₁ + yy₁ = a² (or T = 0) Parametric form: x cosα + y sinα = a


Pair of Tangents from a Point:

SS₁ = T²


Length of a Tangent from External Point (x₁, y₁):

Length = √S₁ (where S₁ = x₁² + y₁² + 2gx₁ + 2fy₁ + c)


Director Circle of x² + y² = a²:

x² + y² = 2a²


Chord of Contact:

T = 0


(i) Length of chord of contact = 2LR/√(R² + L²) (ii) Area of triangle formed by pair of tangents & chord of contact = RL³/√(R² + L²) (iii) Tangent of angle between pair of tangents from (x₁, y₁) = 2RL/(L² − R²) (iv) Equation of circle circumscribing triangle PT₁T₂: (x − x₁)(x + g) + (y − y₁)(y + f) = 0


Condition of Orthogonality of Two Circles:

2g₁g₂ + 2f₁f₂ = c₁ + c₂


Radical Axis:

S₁ − S₂ = 0, i.e., 2(g₁ − g₂)x + 2(f₁ − f₂)y + (c₁ − c₂) = 0


Family of Circles:

S₁ + KS₂ = 0 S + KL = 0


QUADRATIC EQUATIONS

General Form:

ax² + bx + c = 0; a, b, c are constants and a ≠ 0


Roots of Equation:

α = [−b + √(b² − 4ac)] / (2a) β = [−b − √(b² − 4ac)] / (2a)


Sum and Product of Roots:

If α and β are roots of ax² + bx + c = 0: Sum of roots: α + β = −b/a Product of roots: αβ = c/a


Discriminant:

D = b² − 4ac


Nature of Roots:

D = 0 → Roots are real and equal: α = β = −b/(2a) D > 0 → Roots are real and unequal D < 0 → Roots are imaginary and unequal (complex conjugates) D > 0 and D is a perfect square → Roots are rational and unequal D > 0 and D is not a perfect square → Roots are irrational and unequal


Formation of a Quadratic Equation with Given Roots:

(x − α)(x − β) = 0 x² − (α + β)x + αβ = 0 x² − (Sum of roots)x + (Product of roots) = 0


Common Roots:

If two equations a₁x² + b₁x + c₁ = 0 and a₂x² + b₂x + c₂ = 0 have:


Both roots common: a₁/a₂ = b₁/b₂ = c₁/c₂


Only one root α common: α = (c₁a₂ − c₂a₁)/(a₁b₂ − a₂b₁) = (b₁c₂ − b₂c₁)/(c₁a₂ − c₂a₁)


Range of Quadratic Expression f(x) = ax² + bx + c in Restricted Domain x ∈ [x₁, x₂]:

If −b/(2a) does not belong to [x₁, x₂]: f(x) ∈ [min{f(x₁), f(x₂)}, max{f(x₁), f(x₂)}]


If −b/(2a) ∈ [x₁, x₂]: f(x) ∈ [min{f(x₁), f(x₂), −D/(4a)}, max{f(x₁), f(x₂), −D/(4a)}]


Roots Under Special Cases (ax² + bx + c = 0):

c = 0 → One root is zero, other is −b/a b = 0 → Roots are equal in magnitude but opposite in sign b = c = 0 → Both roots are zero a = c → Roots are reciprocal to each other a + b + c = 0 → One root is 1, second root is c/a a = b = c = 0 → Equation becomes an identity (satisfied by every x)


Graph of a Quadratic Equation:

The graph is a parabola. a > 0 → Concave upwards (opens up) a < 0 → Concave downwards (opens down)


Maximum and Minimum Value of ax² + bx + c:

If a < 0 → Greatest (maximum) value at x = −b/(2a). Max value = −D/(4a) If a > 0 → Least (minimum) value at x = −b/(2a). Min value = −D/(4a)


Quadratic Expression in Two Variables:

ax² + 2hxy + by² + 2gx + 2fy + c


Condition for resolution into two linear rational factors:

|a h g| |h b f| = 0 |g f c|


i.e., abc + 2fgh − af² − bg² − ch² = 0 AND h² − ab > 0


BINOMIAL THEOREM

Binomial Theorem for Positive Integral Index:

(x + a)ⁿ = ⁿC₀xⁿa⁰ + ⁿC₁xⁿ⁻¹a + ⁿC₂xⁿ⁻²a² + ... + ⁿCᵣxⁿ⁻ʳaʳ + ... + ⁿCₙxaⁿ


General Term:

T_(r+1) = ⁿCᵣ xⁿ⁻ʳ aʳ


Deductions:

(1 + x)ⁿ = ⁿC₀ + ⁿC₁x + ⁿC₂x² + ⁿC₃x³ + ... + ⁿCᵣxʳ + ... + ⁿCₙxⁿ General term: T_(r+1) = ⁿCᵣ xʳ = [n(n−1)(n−2)...(n−r+1)/r!] × xʳ


(1 − x)ⁿ = ⁿC₀ − ⁿC₁x + ⁿC₂x² − ⁿC₃x³ + ... + (−1)ʳ ⁿCᵣxʳ + ... + (−1)ⁿ ⁿCₙxⁿ General term: T_(r+1) = (−1)ʳ ⁿCᵣ xʳ


Middle Term in (x + a)ⁿ:

Suppose n is even: Middle term = (n/2 + 1)th term. If n is odd: Middle terms are ((n+1)/2)th and ((n+3)/2)th terms. The binomial coefficient of the middle term is the greatest binomial coefficient.


To Determine a Particular Term:

In expansion of (xᵅ ± 1/xᵝ)ⁿ, if xᵐ occurs in T_(r+1): nα − r(α + β) = m → r = (nα − m)/(α + β)


Term independent of x: nα − r(α + β) = 0 → r = nα/(α + β)


To Find a Term from the End:

Tᵣ(E) = T_(n−r+2)(B) (rth term from end = (n − r + 2)th term from beginning)


Binomial Coefficients and Their Properties:

In (1 + x)ⁿ = C₀ + C₁x + C₂x² + ... + Cᵣxʳ + ... + Cₙxⁿ where C₀ = 1, C₁ = n, C₂ = n(n−1)/2!


(i) C₀ + C₁ + C₂ + ... + Cₙ = 2ⁿ (ii) C₀ − C₁ + C₂ − C₃ + ... = 0 (iii) C₀ + C₂ + C₄ + ... = C₁ + C₃ + C₅ + ... = 2ⁿ⁻¹ (iv) C₀² + C₁² + C₂² + ... + Cₙ² = (2n)!/(n!n!) (v) C₀ + C₁/2 + C₂/3 + ... + Cₙ/(n+1) = (2ⁿ⁺¹ − 1)/(n+1) (vi) C₀ − C₁/2 + C₂/3 − C₃/4 + ... + (−1)ⁿCₙ/(n+1) = 1/(n+1)


Greatest Term in (x + a)ⁿ: 

Greatest coefficient: If n is even: T_(n/2+1) If n is odd: T_((n+1)/2) and T_((n+3)/2)


Greatest term: If (n+1)a/(x+a) = p ∈ Z: T_p and T_(p+1) are both greatest If (n+1)a/(x+a) is not integer and q < (n+1)a/(x+a) < q+1: T_(q+1) is greatest


Multinomial Expansion (n ∈ N):

(x₁ + x₂ + x₃ + ... + xₖ)ⁿ = Σ [n!/(r₁!r₂!...rₖ!)] × x₁^r₁ × x₂^r₂ × ... × xₖ^rₖ


where sum is over all r₁ + r₂ + ... + rₖ = n


Binomial Theorem for Negative Integer or Fractional Indices:

(1 + x)ⁿ = 1 + nx + [n(n−1)/2!]x² + [n(n−1)(n−2)/3!]x³ + ... + [n(n−1)(n−2)...(n−r+1)/r!]xʳ + …


Valid for |x| < 1


T_(r+1) = [n(n−1)(n−2)...(n−r+1)/r!] × xʳ


PARABOLA

Estandar parábola y² = 4ax:

Focus: (a, 0), a > 0 Directrix: x = −a Vertex: (0, 0) Axis: y = 0 Length of latus rectum = 4a Ends of latus rectum: L(a, 2a) and L'(a, −2a)


Parametric Representation:

Point on parabola: (at², 2at)


Position of a Point (x₁, y₁) w.r.t. y² = 4ax:

y₁² − 4ax₁ > 0 → Outside y₁² − 4ax₁ = 0 → On the parabola y₁² − 4ax₁ < 0 → Inside


Length of Chord Intercepted by y² = 4ax on line y = mx + c:

Length = (4/m²)√[a(1 + m²)(a − mc)]


Tangent to y² = 4ax:

T = 0 y = mx + a/m, m ≠ 0 is tangent to y² = 4ax at point (a/m², 2a/m)


Normal to y² = 4ax:

At (x₁, y₁): y − y₁ = (−y₁/2a)(x − x₁)


Chord with Given Middle Point (x₁, y₁):

T = S₁ where S₁ = y₁² − 4ax₁


DEFINITE INTEGRATION

Definite Integral as Limit of Sum:

∫(a to b) f(x)dx = Σ(r=1 to n) h·f(a + rh) where h = (b − a)/n


Fundamental Theorem of Calculus:

∫(a to b) f(x)dx = F(b) − F(a), where F'(x) = f(x)


Properties of Definite Integrals:

  1. ∫(a to b) f(x)dx = ∫(a to b) f(t)dt


  1. ∫(a to b) f(x)dx = −∫(b to a) f(x)dx


  1. ∫(a to b) cf(x)dx = c∫(a to b) f(x)dx


  1. ∫(a to b) [f(x) ± g(x)]dx = ∫(a to b) f(x)dx ± ∫(a to b) g(x)dx


  1. ∫(a to b) f(x)dx = ∫(a to c) f(x)dx + ∫(c to b) f(x)dx


  1. ∫(a to b) f(x)dx = ∫(a to b) f(a + b − x)dx


  1. ∫(0 to a) f(x)dx = ∫(0 to a) f(a − x)dx


  1. ∫(0 to 2a) f(x)dx = 2∫(0 to a) f(x)dx if f(2a − x) = f(x)


  1. ∫(0 to 2a) f(x)dx = 0 if f(2a − x) = −f(x)


  1. ∫(−a to a) f(x)dx = 2∫(0 to a) f(x)dx if f(x) is even [f(−x) = f(x)]


  1. ∫(−a to a) f(x)dx = 0 if f(x) is odd [f(−x) = −f(x)]


Definite Integrals Involving Rational/Irrational Expressions:

∫(0 to ∞) dx/(x² + a²) = π/(2a)


∫(0 to ∞) xᵐ dx/(xⁿ + aⁿ) = πa^(m−n+1) / [n sin((m+1)π/n)], 0 < m+1 < n


∫(0 to ∞) x^(p−1) dx/(1+x) = π/sin(pπ), 0 < p < 1


∫(−a to a) dx/√(a² − x²) = π/2


∫(−a to a) √(a² − x²) dx = πa²/4


Definite Integrals Involving Trigonometric Functions:

∫(0 to π) sin(mx)sin(nx)dx = 0 if m ≠ n; = π/2 if m = n (m, n positive integers)


∫(0 to π) cos(mx)cos(nx)dx = 0 if m ≠ n; = π/2 if m = n (m, n positive integers)


∫(0 to π) sin(mx)cos(nx)dx = 0 if m+n is even; = 2m/(m² − n²) if m+n is odd


∫(0 to π/2) sin²x dx = ∫(0 to π/2) cos²x dx = π/4


Walli's Formula:

∫(0 to π/2) sin²ᵐx dx = ∫(0 to π/2) cos²ᵐx dx = [1·3·5...(2m−1)]/[2·4·6...(2m)] × π/2, m = 1,2,...


∫(0 to π/2) sin²ᵐ⁺¹x dx = ∫(0 to π/2) cos²ᵐ⁺¹x dx = [2·4·6...(2m)]/[1·3·5...(2m+1)], m = 1,2,...


Periodic Function Properties:

∫(0 to nT) f(x)dx = n∫(0 to T) f(x)dx, n ∈ Z


∫(a to a+nT) f(x)dx = n∫(0 to T) f(x)dx, n ∈ Z


∫(mT to nT) f(x)dx = (n − m)∫(0 to T) f(x)dx, m, n ∈ Z


∫(nT to a+nT) f(x)dx = ∫(0 to a) f(x)dx


∫(a+nT to b+nT) f(x)dx = ∫(a to b) f(x)dx, n ∈ Z, a, b ∈ R


Leibniz Theorem:

If F(x) = ∫(g(x) to h(x)) f(t)dt, then: dF(x)/dx = h'(x)·f(h(x)) − g'(x)·f(g(x))


ELLIPSE

Standard Equation:

x²/a² + y²/b² = 1, where a > b and b² = a²(1 − e²)


Eccentricity: e = √(1 − b²/a²), 0 < e < 1 Directrices: x = ±a/e Foci: S = (±ae, 0) Vertices: A' = (−a, 0) and A = (a, 0) Length of major axis = 2a, minor axis = 2b Latus Rectum = 2b²/a = 2a(1 − e²)


Auxiliary Circle:

x² + y² = a²


Parametric Representation:

x = a cosθ, y = b sinθ


Position of Point (x₁, y₁) w.r.t. Ellipse:

x₁²/a² + y₁²/b² − 1 > 0 → Outside = 0 → On the ellipse < 0 → Inside


Line and Ellipse:

y = mx + c meets x²/a² + y²/b² = 1 in two points: Real if c² < a²m² + b² Coincident (tangent) if c² = a²m² + b² Imaginary if c² > a²m² + b²


Tangents to Ellipse:

Slope form: y = mx ± √(a²m² + b²) Point form: xx₁/a² + yy₁/b² = 1 Parametric form: (x cosθ)/a + (y sinθ)/b = 1

  

Normal to Ellipse:

At (x₁, y₁): a²x/x₁ − b²y/y₁ = a² − b² Parametric: ax secθ − by cosecθ = a² − b² Slope form: y = mx − (a² − b²)m/√(a² + b²m²)


Director Circle:

x² + y² = a² + b²


INVERSE TRIGONOMETRIC FUNCTIONS

Arcsine (sin⁻¹x):

sin⁻¹(−x) = −sin⁻¹(x), x ∈ [−1, 1] Domain: −1 ≤ x ≤ 1 Range: −π/2 ≤ y ≤ π/2 Derivative: d/dx[sin⁻¹(x)] = 1/√(1 − x²)


Arccosine (cos⁻¹x):

cos⁻¹(−x) = π − cos⁻¹(x), x ∈ [−1, 1] Domain: −1 ≤ x ≤ 1 Range: 0 ≤ y ≤ π Derivative: d/dx[cos⁻¹(x)] = −1/√(1 − x²)


Arctangent (tan⁻¹x):

tan⁻¹(−x) = −tan⁻¹(x), x ∈ R Domain: −∞ ≤ x ≤ ∞ Range: −π/2 ≤ y ≤ π/2 Derivative: d/dx[tan⁻¹(x)] = 1/(1 + x²)


Arc Cotangent (cot⁻¹x):

cot⁻¹(−x) = π − cot⁻¹(x), x ∈ R Domain: −∞ ≤ x ≤ ∞ Range: 0 ≤ y ≤ π Derivative: d/dx[cot⁻¹(x)] = −1/(1 + x²)


Arc Secant (sec⁻¹x):

sec⁻¹(−x) = π − sec⁻¹(x), |x| ≥ 1 Domain: −∞ ≤ x ≤ −1 or 1 ≤ x ≤ ∞ Range: 0 ≤ y ≤ π, y ≠ π/2 Derivative: d/dx[sec⁻¹(x)] = 1/(|x|√(x² − 1))


Arc Cosecant (cosec⁻¹x):

cosec⁻¹(−x) = −cosec⁻¹(x), |x| ≥ 1 Domain: −∞ ≤ x ≤ −1 or 1 ≤ x ≤ ∞ Range: −π/2 ≤ y ≤ π/2, y ≠ 0 Derivative: d/dx[cosec⁻¹(x)] = −1/(|x|√(x² − 1))


STRAIGHT LINES

Distance Formula:

d = √[(x₁ − x₂)² + (y₁ − y₂)²]


Section Formula:

Internal: x = (mx₂ + nx₁)/(m + n); y = (my₂ + ny₁)/(m + n) External: x = (mx₂ − nx₁)/(m − n); y = (my₂ − ny₁)/(m − n)


Centroid:

G = ((x₁ + x₂ + x₃)/3, (y₁ + y₂ + y₃)/3)


Incentre:

I = ((ax₁ + bx₂ + cx₃)/(a+b+c), (ay₁ + by₂ + cy₃)/(a+b+c))


Excentre (opposite to vertex A):

I₁ = ((−ax₁ + bx₂ + cx₃)/(−a+b+c), (−ay₁ + by₂ + cy₃)/(−a+b+c))


Area of Triangle:  

ΔABC = ½|x₁(y₂ − y₃) + x₂(y₃ − y₁) + x₃(y₁ − y₂)| = ½ × determinant |x₁ y₁ 1; x₂ y₂ 1; x₃ y₃ 1|


Slope Formula:

m = (y₁ − y₂)/(x₁ − x₂)


Condition of Collinearity of Three Points:

|x₁ y₁ 1| |x₂ y₂ 1| = 0 |x₃ y₃ 1|


Angle Between Two Straight Lines:

tanθ = |(m₁ − m₂)/(1 + m₁m₂)|


Bisector of Angles Between Two Lines:

(ax + by + c)/√(a² + b²) = ±(a'x + b'y + c')/√(a'² + b'²)


Condition of Concurrency (three lines a_ix + b_iy + c_i = 0, i = 1,2,3):

|a₁ b₁ c₁| |a₂ b₂ c₂| = 0 |a₃ b₃ c₃|


Pair of Straight Lines Through Origin:

ax² + 2hxy + by² = 0


Acute angle θ between them: tanθ = |2√(h² − ab)/(a + b)|


Two Lines ax + bx + c = 0 and a'x + b'y + c' = 0:

Parallel if: a/a' = b/b' ≠ c/c' Distance between parallel lines = |C₁ − C₂|/√(a² + b²) Perpendicular if: aa' + bb' = 0


Point and Line:   

Distance from point (x₁, y₁) to line ax + by + c = 0: = |ax₁ + by₁ + c|/√(a² + b²)


Reflection of point (x₁, y₁) about line ax + by + c = 0: (x − x₁)/a = (y − y₁)/b = −2(ax₁ + by₁ + c)/(a² + b²)


Foot of perpendicular from (x₁, y₁) on line ax + by + c = 0: (x − x₁)/a = (y − y₁)/b = −(ax₁ + by₁ + c)/(a² + b²)


INDEFINITE INTEGRATION

Basic Definition:

If g'(x) = f(x), then ∫f(x)dx = g(x) + c ⟺ d/dx{g(x) + c} = f(x)


Standard Formulas:

∫(ax + b)ⁿ dx = (ax + b)ⁿ⁺¹/[a(n+1)] + c, n ≠ −1 ∫dx/(ax + b) = (1/a) ln|ax + b| + c ∫e^(ax+b) dx = (1/a)e^(ax+b) + c ∫a^(px+q) dx = (1/p) × a^(px+q)/ln(a) + c, a > 0 ∫sin(ax + b) dx = −(1/a)cos(ax + b) + c ∫cos(ax + b) dx = (1/a)sin(ax + b) + c ∫tan(ax + b) dx = (1/a) ln|sec(ax + b)| + c ∫cot(ax + b) dx = (1/a) ln|sin(ax + b)| + c ∫sec²(ax + b) dx = (1/a)tan(ax + b) + c ∫cosec²(ax + b) dx = −(1/a)cot(ax + b) + c ∫sec(x) dx = ln|sec x + tan x| + c = ln|tan(π/4 + x/2)| + c ∫cosec(x) dx = ln|cosec x − cot x| + c = ln|tan(x/2)| + c


Inverse Trigonometric Integrals:

∫dx/√(a² − x²) = sin⁻¹(x/a) + c ∫dx/(a² + x²) = (1/a)tan⁻¹(x/a) + c ∫dx/(|x|√(x² − a²)) = (1/a)sec⁻¹(x/a) + c


Integrals with Square Roots:

∫dx/√(x² + a²) = ln|x + √(x² + a²)| + c ∫dx/√(x² − a²) = ln|x + √(x² − a²)| + c ∫dx/(a² − x²) = (1/2a) ln|(a + x)/(a − x)| + c ∫dx/(x² − a²) = (1/2a) ln|(x − a)/(x + a)| + c


∫√(a² − x²) dx = (x/2)√(a² − x²) + (a²/2)sin⁻¹(x/a) + c ∫√(x² + a²) dx = (x/2)√(x² + a²) + (a²/2) ln|(x + √(x² + a²))/a| + c ∫√(x² − a²) dx = (x/2)√(x² − a²) − (a²/2) ln|(x + √(x² − a²))/a| + c


Integration by Substitution:

If f(x) = t, then f'(x)dx = dt


Integration by Parts:

∫f(x)g(x)dx = f(x)∫g(x)dx − ∫[d/dx(f(x)) × ∫g(x)dx]dx


Integration of Type ∫dx/(ax² + bx + c), ∫dx/√(ax² + bx + c), ∫√(ax² + bx + c)dx:

Substitute x + b/(2a) = t


Trigonometric Integrals:

For ∫dx/(a + b cos²x) or ∫dx/(a + b sin²x) or ∫dx/(a sin²x + b sinx cosx + c cos²x): Put tan x = t


For ∫dx/(a + b sinx) or ∫dx/(a + b cosx) or ∫dx/(a + b sinx + c cosx): Put tan(x/2) = t


Integration of Type ∫(x² + 1)/(x⁴ + Kx² + 1) dx:

Divide numerator and denominator by x², then put x ∓ 1/x = t


APPLICATION OF DERIVATIVES

Equation of Tangent at (x₁, y₁):

y − y₁ = f'(x₁)(x − x₁) (f'(x₁) must be real)


Equation of Normal at (x₁, y₁):  

y − y₁ = −[1/f'(x₁)](x − x₁) (f'(x₁) must be non-zero and real)


Tangent from External Point (a, b) not on curve y = f(x):

Find point of contact (h, f(h)) by solving: f'(h) = [f(h) − b]/(h − a) Then tangent: y − b = [(f(h) − b)/(h − a)](x − a)


Lengths of Tangent, Normal, Subtangent, Subnormal:   

(where k = y₁, m = dy/dx at the point)


Length of tangent PT = |k|√(1 + 1/m²) Length of normal PN = |k|√(1 + m²) Length of subtangent TM = |k/m| Length of subnormal MN = |km|


Angle Between Two Curves:   

tanθ = |(m₁ − m₂)/(1 + m₁m₂)| (m₁, m₂ are slopes of tangents at point of intersection)


Rolle's Theorem:

If f is continuous on [a, b], differentiable on (a, b), and f(a) = f(b), then there exists at least one c ∈ (a, b) such that f'(c) = 0.


Lagrange's Mean Value Theorem (LMVT):

If f is continuous on [a, b] and differentiable on (a, b), then there exists at least one c ∈ (a, b) such that: [f(b) − f(a)]/(b − a) = f'(c)


Formulae of Mensuration:

Volume of cuboid = lbh Surface area of cuboid = 2(lb + bh + hl) Volume of cube = a³ Surface area of cube = 6a² Volume of cone = (1/3)πr²h Curved surface area of cone = πrl (l = slant height) Curved surface area of cylinder = 2πrh Total surface area of cylinder = 2πrh + 2πr² Volume of sphere = (4/3)πr³ Surface area of sphere = 4πr² Area of circular sector = (1/2)r²θ (θ in radians) Volume of prism = (area of base) × height Lateral surface area of prism = (perimeter of base) × height Total surface area of prism = (lateral surface area) + 2(area of base) Volume of pyramid = (1/3)(area of base) × height Curved surface area of pyramid = (1/2)(perimeter of base) × (slant height)


SEQUENCE & SERIES

Arithmetic Progression (A.P.):

a, a+d, a+2d, ..., a+(n−1)d


nth term: tₙ = a + (n − 1)d


Sum of first n terms: Sₙ = (n/2)[2a + (n − 1)d] = (n/2)[a + l] (l = last term)

rth term when sum is given: tᵣ = Sᵣ − Sᵣ₋₁  

 

Properties of A.P.:

If a, b, c are in A.P.: 2b = a + c. If a, b, c, and d are in A.P.: a + d = b + c. Sum of terms equidistant from beginning and end = sum of first and last term


Arithmetic Mean:

If a, b, and c are in A.P., then b is the A.M. of a and c.


n Arithmetic Means between a and b (a, A₁, A₂, ..., Aₙ, b in A.P.): A₁ = a + (b−a)/(n+1) A₂ = a + 2(b−a)/(n+1) ... Aₙ = a + n(b−a)/(n+1)


Σ(r=1 to n) Aᵣ = nA, where A is the single A.M. between a and b


Geometric Progression (G.P.):

a, ar, ar², ar³, ar⁴, …


nth term = arⁿ⁻¹


Sum of first n terms: Sₙ = a(rⁿ − 1)/(r − 1), r ≠ 1 Sₙ = na, r = 1


Sum to infinity (|r| < 1): S∞ = a/(1 − r)


Harmonic Mean:

If a, b, c are in H.P.: b = 2ac/(a + c)


H.M. of a₁, a₂, ..., aₙ: 1/H = (1/n)[1/a₁ + 1/a₂ + ... + 1/aₙ]


Relation Between Means:

G² = AH A.M. ≥ G.M. ≥ H.M. A.M. = G.M. = H.M. if a₁ = a₂ = a₃ = ... = aₙ


Important Summation Results:

Σ(r=1 to n)(aᵣ ± bᵣ) = Σaᵣ ± Σbᵣ Σ(r=1 to n) k·aᵣ = k·Σaᵣ Σ(r=1 to n) k = nk (k = constant) Σ(r=1 to n) r = n(n+1)/2 Σ(r=1 to n) r² = n(n+1)(2n+1)/6 Σ(r=1 to n) r³ = [n(n+1)/2]² = n²(n+1)²/4


HYPERBOLA

Standard Equation:

x²/a² − y²/b² = 1, where b² = a²(e² − 1)


Foci: S ≡ (±ae, 0) Directrices: x = ±a/e Vertices: A ≡ (±a, 0) Eccentricity: e > 1 Latus Rectum: l = 2b²/a = 2a(e² − 1)


Conjugate Hyperbola:

x²/a² − y²/b² = 1 and −x²/a² + y²/b² = 1 are conjugate hyperbolas of each other.


Auxiliary Circle:

x² + y² = a²


Parametric Representation:

x = a secθ, y = b tanθ


Position of Point (x₁, y₁) w.r.t. Hyperbola:

S₁ = x₁²/a² − y₁²/b² − 1 S₁ > 0 → Inside S₁ = 0 → On the hyperbola S₁ < 0 → Outside


Tangents:

Slope form: y = mx ± √(a²m² − b²) Point form: xx₁/a² − yy₁/b² = 1 Parametric form: (x secθ)/a − (y tanθ)/b = 1


Normal:

At (x₁, y₁): a²x/x₁ + b²y/y₁ = a² + b² = a²e². At (a secθ, b tanθ): ax/secθ + by/tanθ = a² + b² = a²e². Slope form: y = mx ± (a² + b²)m/√(a² − b²m²)


Asymptotes:

x/a + y/b = 0 and x/a − y/b = 0 Pair of asymptotes: x²/a² − y²/b² = 0


Rectangular (Equilateral) Hyperbola xy = c²:

Eccentricity = √2 Vertices: (±c, ±c) Foci: (±√2 c, ±√2 c) Directrices: x + y = ±√2 c Latus Rectum: l = 2√2 c = T.A. = C.A.


Parametric equation: x = ct, y = c/t, t ∈ R − {0}


Tangent at (x₁, y₁): x/x₁ + y/y₁ = 2 Tangent at P(t): x/t + ty = 2c Normal at P(t): xt³ − yt = c(t⁴ − 1) Chord with midpoint (h, k): kx + hy = 2hk


Maths is the highest-scoring subject in JEE Advanced if you know your formulas cold. Students who revise formulas daily score 20-30 marks more than those who rely on memory alone. This formula sheet is designed to make that daily revision fast and easy.


Why Vedantu’s JEE Advanced Maths Formula Sheet Matters More Than You Think?

  • Maths has the most formulas of all three subjects: Between Algebra, Calculus, Coordinate Geometry, Trigonometry, and Vectors, there are easily 700+ formulas and results to remember. No one can keep all of them in their head without regular revision.

  • JEE Advanced Maths is speed-dependent: You get about 3 minutes per question. If you waste 30 seconds trying to recall a formula, you lose time for the actual problem-solving. Instant recall is not optional — it is necessary.

  • One wrong formula means one wrong answer: In Physics, you might still get partial understanding marks. In Maths, if you use the wrong formula, you get the wrong answer. There is no partial credit. The formula is either right or it is not.

  • Formulas connect across topics: JEE Advanced loves questions that mix topics. A question might need the section formula from Coordinate Geometry, the dot product from Vectors, and a determinant from Matrices - all in one problem. Having a complete formula sheet helps you see these connections.


Subject Wise Links JEE Advanced 2026 Formulas

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Subject-Wise JEE Advanced 2026 Formulas

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JEE Advanced Physics Formulas 

2

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FAQs on JEE Advanced Maths Formulas 2026: Free Formula Sheet PDF

1. Where can I find the JEE Advanced Maths Formulas PDF?

You can download the JEE Advanced Maths Formulas PDF directly from Vedantu’s website. It contains all the essential formulas for JEE Advanced Mathematics.

2. What are the most important maths formulas for JEE Advanced?

Some of the most important maths formulas for JEE Advanced include those for differentiation, integration, vectors, and coordinate geometry. These are crucial for solving high-weightage problems in the exam.

3. Can I download the JEE Advanced Maths Formulas PDF for free?

Yes, the JEE Advanced Maths Formulas PDF is available for free download on Vedantu's website. Access the complete list of formulas at no cost to aid your revision.

4. How can the JEE Advanced Maths Formula Sheet help in exam preparation?

The JEE Advanced Maths Formula Sheet is a quick-reference guide that helps students revise essential formulas and solve problems faster during the JEE Advanced 2026 exam.

5. How can I use the JEE Advanced Maths Formulas PDF to improve my score?

By using the JEE Advanced Maths Formulas PDF, you can quickly memorise key formulas and apply them effectively to practice problems, boosting your speed and accuracy in the exam.

6. What’s included in the JEE Advanced Maths Formulas PDF for 2026?

The JEE Advanced Maths Formulas PDF for 2026 includes formulas for all key topics, including differentiation, integration, vectors, and geometry, to help you prepare thoroughly.

7. Are the JEE Advanced Maths Formulas PDF downloadable for offline use?

Yes, the JEE Advanced Maths Formulas PDF is available for offline download. You can download it from Vedantu’s website and access it anytime during your preparation.

8. How can the JEE Advanced Mathematics Formulas help with time management during the exam?

The JEE Advanced Mathematics Formulas sheet helps with time management by allowing you to quickly access critical equations, reducing the time spent searching for formulas during the exam.

9. What is the best way to study with the JEE Advanced Maths Formulas PDF?

To study effectively with the JEE Advanced Maths Formulas PDF, go through the formulas regularly, make sure you understand their application, and practice problems that use them. This will ensure you're well-prepared for the exam.

10. How do I ensure I remember the JEE Advanced Maths Formulas for 2026?

Repetition and practice are key. Use the JEE Advanced Maths Formula Sheet to test yourself on each formula regularly. Focus on applying them while solving past exam papers and mock tests.