
\[\int_{ - 4}^4 {\left| {x + 2} \right|} dx = \]
A) \[50\]
B) \[24\]
C) \[20\]
D) None of these
Answer
228k+ views
Hint: in this question, we have to find the given integral. In order to find this, the properties of modulus and formula of definite integral is used. Break modulus function into two limits one part is for negative limit and other for positive limit.
Formula Used: The definite integral is the area under the curve between two fixed limits.
Let f(x) is a function and suppose integration of function f(x) is F(x) then definite integral of f(x) having upper limit b and lower limit a can be written in mathematical expression as
\[\int_a^b {f(x)} dx = F(b) - F(a)\]
b is upper limit of integral and a is a lower limit of integral.
Property of mod function
If limit is less than zero
\[\left| {f(x)} \right| = - f(x)\]
If limit of function is greater than zero
\[\left| {f(x)} \right| = f(x)\]
Complete step by step solution: Given: Definite integral \[\int_{ - 4}^4 {\left| {x + 2} \right|} dx\]
Here in this integral upper limit is \[4\]and lower limit is \[ - 4\]
\[\int_{ - 4}^4 {\left| {x + 2} \right|} dx = \int_{ - 4}^{ - 2} { - (x + 2)} dx + \int_{ - 2}^4 {(x + 2)} dx\]
\[\int_{ - 4}^{ - 2} { - (x + 2)} dx + \int_{ - 2}^4 {(x + 2)} dx = [\dfrac{{ - {x^2}}}{2} - 2x]_{ - 4}^{ - 2} + [\dfrac{{{x^2}}}{2} + 2x]_{ - 2}^4\]
\[\begin{array}{l}[\dfrac{{ - {x^2}}}{2} - 2x]_{ - 4}^{ - 2} + [\dfrac{{{x^2}}}{2} + 2x]_{ - 2}^4 = [( - 2 + 4) - (8 + 8)] + [(8 + 8) - (2 - 4)]\\\end{array}\]
\[\begin{array}{l}[( - 2 + 4) - (8 + 8)] + [(8 + 8) - (2 - 4)] = 2 + 16 + 2\\\end{array}\]
\[ = 20\]
So required definite integral is
\[20\]
Option ‘C’ is correct
Note: We must remember that mod function always give positive value. So to make modulus positive break the function of modulus into two different limit.
The definite integral is the area under the curve between two fixed limits.
Let f(x) is a function and suppose integration of function f(x) is F(x) then definite integral of f(x) having upper limit b and lower limit a can be written in mathematical expression as
\[\int_a^b {f(x)} dx = F(b) - F(a)\]
Properties of the definite integrals are:
1) Interchanging the upper and lower limit: \[\int_b^a {f(x)} dx = - \int_a^b {f(x)} dx\]
2) \[\int_b^a {f(x)} dx = \int_b^a {f(t)} dt\]
3) \[\int_0^a {f(x)} dx = \int_0^a {f(a - x)} dx\]
4) \[\int_a^b {f(x)} dx = \int_a^c {f(x)} dx + \int_c^b {f(x)} dx\]
Formula Used: The definite integral is the area under the curve between two fixed limits.
Let f(x) is a function and suppose integration of function f(x) is F(x) then definite integral of f(x) having upper limit b and lower limit a can be written in mathematical expression as
\[\int_a^b {f(x)} dx = F(b) - F(a)\]
b is upper limit of integral and a is a lower limit of integral.
Property of mod function
If limit is less than zero
\[\left| {f(x)} \right| = - f(x)\]
If limit of function is greater than zero
\[\left| {f(x)} \right| = f(x)\]
Complete step by step solution: Given: Definite integral \[\int_{ - 4}^4 {\left| {x + 2} \right|} dx\]
Here in this integral upper limit is \[4\]and lower limit is \[ - 4\]
\[\int_{ - 4}^4 {\left| {x + 2} \right|} dx = \int_{ - 4}^{ - 2} { - (x + 2)} dx + \int_{ - 2}^4 {(x + 2)} dx\]
\[\int_{ - 4}^{ - 2} { - (x + 2)} dx + \int_{ - 2}^4 {(x + 2)} dx = [\dfrac{{ - {x^2}}}{2} - 2x]_{ - 4}^{ - 2} + [\dfrac{{{x^2}}}{2} + 2x]_{ - 2}^4\]
\[\begin{array}{l}[\dfrac{{ - {x^2}}}{2} - 2x]_{ - 4}^{ - 2} + [\dfrac{{{x^2}}}{2} + 2x]_{ - 2}^4 = [( - 2 + 4) - (8 + 8)] + [(8 + 8) - (2 - 4)]\\\end{array}\]
\[\begin{array}{l}[( - 2 + 4) - (8 + 8)] + [(8 + 8) - (2 - 4)] = 2 + 16 + 2\\\end{array}\]
\[ = 20\]
So required definite integral is
\[20\]
Option ‘C’ is correct
Note: We must remember that mod function always give positive value. So to make modulus positive break the function of modulus into two different limit.
The definite integral is the area under the curve between two fixed limits.
Let f(x) is a function and suppose integration of function f(x) is F(x) then definite integral of f(x) having upper limit b and lower limit a can be written in mathematical expression as
\[\int_a^b {f(x)} dx = F(b) - F(a)\]
Properties of the definite integrals are:
1) Interchanging the upper and lower limit: \[\int_b^a {f(x)} dx = - \int_a^b {f(x)} dx\]
2) \[\int_b^a {f(x)} dx = \int_b^a {f(t)} dt\]
3) \[\int_0^a {f(x)} dx = \int_0^a {f(a - x)} dx\]
4) \[\int_a^b {f(x)} dx = \int_a^c {f(x)} dx + \int_c^b {f(x)} dx\]
Recently Updated Pages
What is the solution of the differential equation edfracdydx class 11 maths JEE_Advanced

In a GP of 3rmn terms S1 denotes the sum of first rmn class 11 maths JEE_Advanced

In an isosceles triangle ABC the coordinates of the class 11 maths JEE_Advanced

If a1+left sqrt31 right+left sqrt31 right2+left sqrt31 class 11 maths JEE_Advanced

What is the value of the integral intlimits 11 sin class 11 maths JEE_Advanced

int 44 left x + 2 right dx A 50 B 24 C 20 D None of class 11 maths JEE_Advanced

Trending doubts
JEE Advanced Marks vs Ranks 2025: Understanding Category-wise Qualifying Marks and Previous Year Cut-offs

JEE Advanced 2026 - Exam Date (Released), Syllabus, Registration, Eligibility, Preparation, and More

JEE Advanced Weightage 2025 Chapter-Wise for Physics, Maths and Chemistry

JEE Advanced 2026 Revision Notes for Practical Organic Chemistry

IIT CSE Cutoff: Category‐Wise Opening and Closing Ranks

IIT Fees Structure 2025

Other Pages
JEE Main 2026: Admit Card Out, City Intimation Slip, Exam Dates, Syllabus & Eligibility

JEE Main 2026 Application Login: Direct Link, Registration, Form Fill, and Steps

Understanding the Angle of Deviation in a Prism

Hybridisation in Chemistry – Concept, Types & Applications

How to Convert a Galvanometer into an Ammeter or Voltmeter

NCERT Solutions For Class 11 Maths Chapter 10 Conic Sections (2025-26)

