
Two streams of photons, possessing energies equal to twice and ten times the work function of metal are incident on the metal surface successively. The value of the ratio of maximum velocities of the photoelectrons emitted in the two respective cases is x :\[3\]. The value of x is ________.
Answer
222k+ views
Hint: When a radiation of sufficient energy greater than the work function of the metal is incident on a metal surface, the electrons inside the atoms of metal surface gain energy and eject out of the surface. This is the Einstein theory of radiation.
By planck's law, \[E{\text{ }} = {\text{ }}h\nu \]where 'h' is known as Planck's constant having value \[6.63{\left( {10} \right)^{34}}\]J s, and 'ν' is the frequency of radiation.
According to Einstein photoelectric equation, kinetic energy.\[ = {\text{ }}h\nu {\text{ }}-{\text{ }}\Phi \] where \[\Phi \]is known as work function.
Formula used:
Photo electric work function:
\[E = {E_0} - {\text{ }}\Phi \]
Complete answer:
Combining the two laws, one given by plank and other by Einstein
\[E = {E_0} - {\text{ }}\Phi \]
It is given that, \[E_0\] for the first photon:
\[ = E{0_1} = {\text{ }}2{\text{ }}\Phi \]
(as photon possesses energy equal to twice the work function of metal).
\[E_0\] for second photon
\[ = E{0_2} = {\text{ }}10{\text{ }}\Phi \]
(as second photon possesses energy equal to ten times the work function of metal)
Thus,
\[{E_1} = 2{\text{ }}\Phi {\text{ }}-{\text{ }}\Phi = \Phi \]
\[{E_2} = 10{\text{ }}\Phi {\text{ }}-{\text{ }}\Phi = 9\Phi \]
Kinetic energy also is dependent on velocity and mass by the relation
\[E = \dfrac{1}{2}m{v^2}\]
Where v is the velocity of a photon. Mass is a constant value hence gets cancelled when the ratio of first photon to the second photon is taken.
Therefore,
\[\dfrac{{{E_1}}}{{{E_2}}} = \dfrac{{{V_1}^2}}{{{V_2}^2}}\]
\[\dfrac{1}{9} = \dfrac{{{V_1}^2}}{{{V_2}^2}}\]
The ratio of maximum velocities of the photoelectrons emitted in the two respective cases is x : 3.
Thus,
\[\dfrac{1}{3} = \dfrac{{{V_1}}}{{{V_2}^{}}}\]
\[\dfrac{1}{3} = \dfrac{x}{3}\]
$x = 3$
Thus, the value of x is $3$.
Note: Minimum energy required for emission of electrons from the surface of metal is called the threshold frequency. The speed and number of the emitted electrons will depend on two factors, namely the colour and intensity of the incident radiation.
By planck's law, \[E{\text{ }} = {\text{ }}h\nu \]where 'h' is known as Planck's constant having value \[6.63{\left( {10} \right)^{34}}\]J s, and 'ν' is the frequency of radiation.
According to Einstein photoelectric equation, kinetic energy.\[ = {\text{ }}h\nu {\text{ }}-{\text{ }}\Phi \] where \[\Phi \]is known as work function.
Formula used:
Photo electric work function:
\[E = {E_0} - {\text{ }}\Phi \]
Complete answer:
Combining the two laws, one given by plank and other by Einstein
\[E = {E_0} - {\text{ }}\Phi \]
It is given that, \[E_0\] for the first photon:
\[ = E{0_1} = {\text{ }}2{\text{ }}\Phi \]
(as photon possesses energy equal to twice the work function of metal).
\[E_0\] for second photon
\[ = E{0_2} = {\text{ }}10{\text{ }}\Phi \]
(as second photon possesses energy equal to ten times the work function of metal)
Thus,
\[{E_1} = 2{\text{ }}\Phi {\text{ }}-{\text{ }}\Phi = \Phi \]
\[{E_2} = 10{\text{ }}\Phi {\text{ }}-{\text{ }}\Phi = 9\Phi \]
Kinetic energy also is dependent on velocity and mass by the relation
\[E = \dfrac{1}{2}m{v^2}\]
Where v is the velocity of a photon. Mass is a constant value hence gets cancelled when the ratio of first photon to the second photon is taken.
Therefore,
\[\dfrac{{{E_1}}}{{{E_2}}} = \dfrac{{{V_1}^2}}{{{V_2}^2}}\]
\[\dfrac{1}{9} = \dfrac{{{V_1}^2}}{{{V_2}^2}}\]
The ratio of maximum velocities of the photoelectrons emitted in the two respective cases is x : 3.
Thus,
\[\dfrac{1}{3} = \dfrac{{{V_1}}}{{{V_2}^{}}}\]
\[\dfrac{1}{3} = \dfrac{x}{3}\]
$x = 3$
Thus, the value of x is $3$.
Note: Minimum energy required for emission of electrons from the surface of metal is called the threshold frequency. The speed and number of the emitted electrons will depend on two factors, namely the colour and intensity of the incident radiation.
Recently Updated Pages
Crack JEE Advanced 2026 with Vedantu's Live Classes

JEE Advanced 2021 Physics Question Paper 2 with Solutions

JEE Advanced 2026 Revision Notes for Chemistry Energetics - Free PDF Download

JEE Advanced 2022 Chemistry Question Paper 2 with Solutions

JEE Advanced 2022 Physics Question Paper 2 with Solutions

JEE Advanced Marks vs Rank 2025 - Predict IIT Rank Based on Score

Trending doubts
JEE Advanced Marks vs Ranks 2025: Understanding Category-wise Qualifying Marks and Previous Year Cut-offs

JEE Advanced Weightage 2025 Chapter-Wise for Physics, Maths and Chemistry

Diffraction of Light - Young’s Single Slit Experiment

JEE Advanced 2026 Revision Notes for Practical Organic Chemistry

JEE Advanced 2026 Notes

Difference Between Exothermic and Endothermic Reactions Explained

Other Pages
JEE Main 2026: Application Form Open, Exam Dates, Syllabus, Eligibility & Question Papers

Derivation of Equation of Trajectory Explained for Students

Hybridisation in Chemistry – Concept, Types & Applications

Understanding the Angle of Deviation in a Prism

Dual Nature of Radiation and Matter Class 12 Physics Chapter 11 CBSE Notes - 2025-26

How to Convert a Galvanometer into an Ammeter or Voltmeter

